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$$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2 \cdot a}$$
Let $x = \frac{1}{2}$.
[ \frac{1}{2} ]
( \frac{1}{2} )
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$$ \int {\frac{1}{11+61 \sin{x}}} ,\mathrm{d}x $$
$$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2 \cdot a}$$
